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I asked my math teacher this, he said he will deliver an answer on Tuesday.

 

0.999... (0.9 when 9 repeats an infinite amount of times) is equal to one. Or so it says. There is proof of this:

 

1 = 3/3 = 3 x 1/3 = 3 x 0.333... = 0.999...

 

So that is proven. But I'm thinking that maybe it's not equal. I could be 100% wrong, so please state if I am.

 

0.999999...

0.000000...1

 

The first number simply means 0.9 when 9 is repeated an infinite amount of times.

 

The second number, however, means 0.01 when the 0 before 1 is repeated an infinite amount of times. This would effectively produce:

 

0.0000000000000000000000000000000000000000...1

 

Also:

 

0.9 + 0.1 = 1

0.99 + 0.01 = 1

0.999 + 0.001 = 1

0.9999 + 0.0001 = 1

0.99999 + 0.00001 = 1

...

0.999... + 0.000...1 = 1

 

When you add two numbers together, assuming neither one is zero, you cannot be adding the sum. Meaning:

 

When you reach a sum of 50, and neither number is zero, you will not be adding 50 with another number.

 

Basically, I said that when you are adding 0.999... with another number not zero to equal 1, 0.999... cannot equal one.

 

The only possible way I am wrong is if 0.000...1 is equal to 0.

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0.999... does not equal 1' date=' and 0.000...1 does not equal 0.

 

We just round them up or down for the sake of simplicity.

 

Yet another stupid question.

 

 

EDIT: I'm also highly disappointed by the lack of food in this topic. I was hungry.

[/quote']

0.9999999999999999 does NOT equal 1. Maybe it equals to 99.9%' date=' but not totally.

 

Simply because 1/3 =/= 0.3333333333333...

There is no real number for 1/3, only an irreal.

Same for 0.oooooo...oooo1 and 0.

[/quote']

 

1 = 3/3 = 3 x 1/3 = 3 x 0.333... = 0.999...

 

All I know is that 1/3 DOES in fact equal 0.333... I can prove that.

 

My question is, if 0.999... equals 1, than 0.000...1 must equal 0, but there is no proof of that.

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Guest JoshIcy

this is a children's card game forum

 

[/thread]

 

This poster is obviously spamming.

 

[/thread]

 

As for this thread itself... Well...

Just round up and stop complaining.

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i see how that math works.. you substitute in the .33333... for 1/3 in the expression and then when you multiply you will supposedly get .9999...

 

but when you substitute a number equal to 1/3 for the place of 1/3, dont you get the same number?

 

see, when you divide 3 by the infinitely going .33333... you should never end up getting .9999... for the sake that .3 repeated is equal to 1/3. always. You will end up with 1 no matter what, not .9 repeated.

 

at least that is what makes sense to me. please point out if i am wrong, as i am very interested in this.

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I am assuming that 0.999... equals 1 based on the fact that 3 x 0.333... also equals one.

 

And would it be possible to have a number such as 0.000...1? Wouldn't that technically be impossible, as it would be an infinite amount of zeros, therefore making it zero? And you'd never be able to reach the one?

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No' date=' 0.999999... =/ 1

 

Many numbers have the same problem.

 

1/3 = 0.3333... BUT 0.33333... x 3 =/ 1. YET 0.999.../3 = 0.333... AND 0.333... x 3 = 0.999...

[/quote']

 

1/3 = 0.333...

Therefore:

0.333... x 3 = 0.999... (using your logic)

 

X/X = 1

Therefore:

3/3 = 1 (using simple math)

 

1 = 3/3

3/3 = 3 x 1/3

3 x 1/3 = 3 x 0.333...

3 x 0.333... = 0.999...

 

Therefore:

 

1 = 0.999...

 

If that is not true, what did I do wrong?

 

EDIT: Also:

 

1/3 = 0.333...

Therefore:

1 / 3 = 0.333...

 

0.999... / 3 = 0.333...

 

0.999... / 3 = 1 / 3

 

Multiply by 3.

 

0.999... = 1

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