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-4^2=_____


+Jono

-4^2 = _______  

1 member has voted

  1. 1. -4^2 = _______

    • -16
      0
    • 16
    • Other (for idiots)


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Actually' date=' there is a third answer.

[/quote']

 

And' date=' yes, I'm aware that "Other" is the correct answer.

[/quote']

 

Whatever the hell you want "Other" to be. I just wanted to see how many people here could do some simple algebra. Not the complicated solutions. Oh and I saw this question elsewhere and an IB student managed to answer the question using his "superior knowledge". Just goes to show, there are alot of different ways to get answers out there. I'm looking for the people who can answer it simply. In other words, the way Larxene answered it. Turns out not many people on this site are able to do that. Big surprise. =\

 

Well then.

What about 2^-4? hrm?

 

Not relevant. But if you really want to know, the answer is 0.0625.

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It could be either.

 

But for sure...

 

-(4)^2 = -16

(-4)^2 = 16

 

You fail. There are no brackets. This is how it goes.

 

-4^2=?

So first we state that 4=2+2:

-(2+2)^2=?

Then we state the the entire equation can be divided by two now:

-(1+1)^1=?/2

The logical next step is two combine the two ones:

-(2)^1=?/2

Since we don't need the brackets they can disappear:

-2^1=?/2

To remove the negative we must turn the other side of the equation negative:

2^1=-?/2

To finish this side we continue to say that "^1" is actually doing nothing:

2=-?/2

Then we multiply both sides by two:

4=-?

The we remove the negative to solve the equation:

-4=?

 

Therefore -4^2= -4

 

With this I conclude that "^2" is the same as "^1" and that both numbers are the same.

1=2

And therefore your teachers just need to shut up because they are wrong.

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It could be either.

 

But for sure...

 

-(4)^2 = -16

(-4)^2 = 16

 

You fail. There are no brackets. This is how it goes.

 

-4^2=?

So first we state that 4=2+2:

-(2+2)^2=?

Then we state the the entire equation can be divided by two now:

-(1+1)^1=?/2

The logical next step is two combine the two ones:

-(2)^1=?/2

Since we don't need the brackets they can disappear:

-2^1=?/2

To remove the negative we must turn the other side of the equation negative:

2^1=-?/2

To finish this side we continue to say that "^1" is actually doing nothing:

2=-?/2

Then we multiply both sides by two:

4=-?

The we remove the negative to solve the equation:

-4=?

 

Therefore -4^2= -4

 

With this I conclude that "^2" is the same as "^1" and that both numbers are the same.

I think you just won the thread.

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It could be either.

 

But for sure...

 

-(4)^2 = -16

(-4)^2 = 16

 

You fail. There are no brackets. This is how it goes.

 

-4^2=?

So first we state that 4=2+2:

-(2+2)^2=?

Then we state the the entire equation can be divided by two now:

-(1+1)^1=?/2

The logical next step is two combine the two ones:

-(2)^1=?/2

Since we don't need the brackets they can disappear:

-2^1=?/2

To remove the negative we must turn the other side of the equation negative:

2^1=-?/2

To finish this side we continue to say that "^1" is actually doing nothing:

2=-?/2

Then we multiply both sides by two:

4=-?

The we remove the negative to solve the equation:

-4=?

 

Therefore -4^2= -4

 

With this I conclude that "^2" is the same as "^1" and that both numbers are the same.

I think you just won the thread.

 

No actually he failed simple math with that.

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Hey' date=' I said that in my above post! It's basically retarded 7th grade math that I did last year.

[/quote']

 

I know, I wasn't saying you couldn't do it or hadn't already done it, I was just saying there were people that couldn't. Prime example:

 

It could be either.

 

But for sure...

 

-(4)^2 = -16

(-4)^2 = 16

 

You fail. There are no brackets. This is how it goes.

 

-4^2=?

So first we state that 4=2+2:

-(2+2)^2=?

Then we state the the entire equation can be divided by two now:

-(1+1)^1=?/2

The logical next step is two combine the two ones:

-(2)^1=?/2

Since we don't need the brackets they can disappear:

-2^1=?/2

To remove the negative we must turn the other side of the equation negative:

2^1=-?/2

To finish this side we continue to say that "^1" is actually doing nothing:

2=-?/2

Then we multiply both sides by two:

4=-?

The we remove the negative to solve the equation:

-4=?

 

Therefore -4^2= -4

 

With this I conclude that "^2" is the same as "^1" and that both numbers are the same.

1=2

And therefore your teachers just need to shut up because they are wrong.

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