Gogeta™ Posted June 19, 2008 Report Share Posted June 19, 2008 I just had a thought, ok theres a different 8 dight code for each card right? Well how long can cards keep being made with different digits? Link to comment Share on other sites More sharing options...
Lucas Maximus Posted June 19, 2008 Report Share Posted June 19, 2008 There are exactly 43046721 possible combinations using 8 digits from 1 to 9. Link to comment Share on other sites More sharing options...
HelioSpark Posted June 19, 2008 Report Share Posted June 19, 2008 a long, long, long, long, long time I learned how to figure this out in math class earlier this year.....but I forget the equation>.> Link to comment Share on other sites More sharing options...
Gogeta™ Posted June 19, 2008 Author Report Share Posted June 19, 2008 There are exactly 43046721 possible combinations using 8 digits from 1 too 9. And there are 2400+ cards already made so yeah there is a long way to go. And theres about 3 packs released every year and about 60 cards a pack. Link to comment Share on other sites More sharing options...
Umbra Posted June 19, 2008 Report Share Posted June 19, 2008 Simply put: A card can use 10 possible digits (0-9) and there are 8 spots. The equation is x^y, where x is the number of possible digits, and y is the number of spots. We then get 10^8, or 100 millions. Link to comment Share on other sites More sharing options...
Mad Hopz Posted June 19, 2008 Report Share Posted June 19, 2008 Simplifying all other posts, we still have a long way to go... Link to comment Share on other sites More sharing options...
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