Valkyrie Lupia Blitzer Posted December 8, 2008 Report Share Posted December 8, 2008 Because 0 is less than 1? @_@ 0^0 should be 0. Link to comment Share on other sites More sharing options...
ragnarok1945 Posted December 8, 2008 Report Share Posted December 8, 2008 0 multiplied by anything, no matter how many times remains 0, Flinsbon. So obvious 0^0 should be 0 Link to comment Share on other sites More sharing options...
Flinsbon Posted December 8, 2008 Report Share Posted December 8, 2008 Yes, but the calculator says 0^0 = Domain error. And it says error on the table at X = 0 when I graph 0^X. I need a why! Link to comment Share on other sites More sharing options...
Dark Posted December 8, 2008 Author Report Share Posted December 8, 2008 1^0 is 12^0 is 13^0 is 1X^0 is 1 What you are doing, is taking X, and multiplying it to equal one. 0 times ANYTHING cannot equal one. So it is undefined. Link to comment Share on other sites More sharing options...
ragnarok1945 Posted December 8, 2008 Report Share Posted December 8, 2008 Yes' date=' but the calculator says 0^0 = Domain error. And it says error on the table at X = 0 when I graph 0^X. I need a why![/quote'] You cannot graph 0^X because any X value will remain 0 Remember, 0^X is just 0*0*0*0*0*0................X number of times, and that's still going to be 0 at the end, so there's literally no graph Link to comment Share on other sites More sharing options...
Flinsbon Posted December 8, 2008 Report Share Posted December 8, 2008 2^X goes like this starting at X = 3 8,4,2 2^0 = 1 because it follows the pattern of /2 X^0 gos like this starting at X=3 0,0,0 Now why does 0^0 not follow the pattern? And is it an imaginary number? Link to comment Share on other sites More sharing options...
Valkyrie Lupia Blitzer Posted December 8, 2008 Report Share Posted December 8, 2008 And it says error on the table at X = 0 when I graph 0^X. I need a why! Vertical slopes are undefined. However, X=0 should be the y-axis. Link to comment Share on other sites More sharing options...
ragnarok1945 Posted December 8, 2008 Report Share Posted December 8, 2008 it's not imaginary, it's just so rarely ever done nobody bothers to give such an answer Link to comment Share on other sites More sharing options...
Valkyrie Lupia Blitzer Posted December 8, 2008 Report Share Posted December 8, 2008 it's not imaginary' date=' it's just so rarely ever done nobody bothers to give such an answer[/quote'] And yet nobody tries to give 124872057017250^129486210357120957190423 an answer, because it's so rarely done. However, the answer not imaginary. Link to comment Share on other sites More sharing options...
Flinsbon Posted December 8, 2008 Report Share Posted December 8, 2008 OK, if 1^0 = 1 and -1^0 = 1 then why doesn't 0^0 = 1? Link to comment Share on other sites More sharing options...
ragnarok1945 Posted December 8, 2008 Report Share Posted December 8, 2008 any number^0 = 1. 0 is the only exception to this rule (should be written in books) Link to comment Share on other sites More sharing options...
Flinsbon Posted December 8, 2008 Report Share Posted December 8, 2008 I know that. What I want to know is WHY 0 is the exception. Link to comment Share on other sites More sharing options...
ragnarok1945 Posted December 8, 2008 Report Share Posted December 8, 2008 look, with all other numbers ^0, like 5^0, it's the same thing as saying 5^2 / 5^2 due to basic properties of exponents, so 5^0 = 1, and this applies to every other number. Link to comment Share on other sites More sharing options...
Flinsbon Posted December 8, 2008 Report Share Posted December 8, 2008 Now that is the help I needed! I get it. It would be like 0^2/0^2, which isn't 1, but is undefined as we settled earlier. Good job! Link to comment Share on other sites More sharing options...
Dark Posted December 8, 2008 Author Report Share Posted December 8, 2008 Ugh... 2^0 is 1 How did we arrive at this? When you raise something to a power of 0' date=' you are arriving at one, all the time. This is because you are multiplying by the multiplicative inverse. 2^0 = 2 x 1/2 = 1 But 0 is the exception to the rule. 0^0 = 0 x 0/0 = 1 You are taking 0 and multiplying it by 0 divided by 0, the inverse. That would get you to an answer of 0/0, which is undefined. No matter what number you multiply 0 by, you will NEVER get 1. So 0^0 is undefined.[/quote'] Link to comment Share on other sites More sharing options...
Flinsbon Posted December 8, 2008 Report Share Posted December 8, 2008 I get it now. Thanks! Link to comment Share on other sites More sharing options...
ragnarok1945 Posted December 8, 2008 Report Share Posted December 8, 2008 Now that is the help I needed! I get it. It would be like 0^2/0^2' date=' which isn't 1, but is undefined as we settled earlier. Good job![/quote'] yeah but the rule does not apply to 0 Link to comment Share on other sites More sharing options...
Dark Posted December 8, 2008 Author Report Share Posted December 8, 2008 Don't thank me, thank the Math Book! But I still don't understand why 0/0 is undefined. My book says nothing. Link to comment Share on other sites More sharing options...
Valkyrie Lupia Blitzer Posted December 8, 2008 Report Share Posted December 8, 2008 Ah. http://en.wikipedia.org/wiki/Exponent#Zero_to_the_zero_power Confusing crap. However, 0^0 is debated. So, we don't know if 0 is an exception to n^0=1 or not. Next question! Link to comment Share on other sites More sharing options...
Flinsbon Posted December 8, 2008 Report Share Posted December 8, 2008 It's saying that, by the exponent rule in division, 0^0 can be written as 0^2/0^2 because 2-2 = 0. However, this problem is undefined because 0^2 = 0 and places 0 in the denominator. OK next question. Not math, but how do we stop a meteor from hitting the Earth if a failure to do so would end all life on Earth? Link to comment Share on other sites More sharing options...
ragnarok1945 Posted December 8, 2008 Report Share Posted December 8, 2008 First off tell us how big the meteor is, and its speed. Link to comment Share on other sites More sharing options...
Flinsbon Posted December 8, 2008 Report Share Posted December 8, 2008 Size and speed = that of the meteor that supposedly wiped out the dinosaurs. Link to comment Share on other sites More sharing options...
ragnarok1945 Posted December 8, 2008 Report Share Posted December 8, 2008 ok so it's not that bad. Just send up a few hundred nuclear warheads. Denote near the meteor and force it to bounce into a different orbit. Link to comment Share on other sites More sharing options...
Flinsbon Posted December 8, 2008 Report Share Posted December 8, 2008 Wouldn't that kill us from radiation, anyway? Link to comment Share on other sites More sharing options...
Valkyrie Lupia Blitzer Posted December 8, 2008 Report Share Posted December 8, 2008 Sorry, this is a math topic. What rangarok1945 said, but I don't know anything about the subject. How about this: Why does 0.999999999999999999999.....=1? Supposedly, 0.999.... would be a very tiny bit less than 1, but that is not the case... I just feel like testing people. Link to comment Share on other sites More sharing options...
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