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[DISC] Everliving Underworld Cannon


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The probability of drawing all three copies of a card is the same as the probability of drawing three specific Limited cards.

 

This card is basically unsearchable.

 

I believe thats not right.

 

It would be 1 Unlimited' date=' 1 Semi-Limited, and one Limited.

 

It is unsearchable though.

 

The "Once per turn" killed it.

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You are incorrect. It would be 3 Limited.

 

With this, you have three specific individual cards in your deck, all of which must be drawn. This is what 3 Limited would produce.

 

With 1 Unlimited, 1 Semi-Limited, and 1 Limited, there are six possible combinations of 3 cards that will work, rather than just one combination.

 

I understand the all 3 limited part. But, when drawing the first, there are 3 in the deck, when drawing the second there are 2 left, and the last one is, obviously, the last one.

 

 

Is there something I am overlooking?

 

Suppose you need an Unlimited, a Semi-Limited, and a Limited. When drawing for the first, there are 6 in the deck. When drawing for the second, there are either 3, 4, or 5 in the deck, depending on which one you go t first. And the last one could have 1, 2, or 3 targets.

 

The difference is that you are assuming that the Unlimited card must be drawn first and will always be drawn first.

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