Man0waR Posted February 17, 2009 Report Share Posted February 17, 2009 my claculus professor gave me this- find the derivative if functions K and G are such that: [K]-34.99+[G(X+2x7)]=[G] it makes NO since. but derivative functions are SO easy (like cal.1 easy...) Link to comment Share on other sites More sharing options...
Azuh Posted February 17, 2009 Report Share Posted February 17, 2009 The answer is 42 Why? It always is Link to comment Share on other sites More sharing options...
Man0waR Posted February 17, 2009 Author Report Share Posted February 17, 2009 LOL. No. It was a trick!! He said this when he gave me the problem. "Ill buy you a steak if you solve this. Any price, size whatever." Today- "on one condition. You have to eat it in one bite." Link to comment Share on other sites More sharing options...
Sander Posted February 17, 2009 Report Share Posted February 17, 2009 What makes no sense that you are asking Calculus help from a Children's Card Game Forum =/ Ask your parents or your gf, not from from a random 12 year old =/ Link to comment Share on other sites More sharing options...
legendhiro Posted February 18, 2009 Report Share Posted February 18, 2009 dude, my head can easily wrap around everything, from chemistry to quantum mechanics to metaphysics, but ask me a calculus question and i freeze up. math is my immortal enemy.unless being used for something scientific. Link to comment Share on other sites More sharing options...
Careless Whisper Posted February 18, 2009 Report Share Posted February 18, 2009 What makes no sense that you are asking Calculus help from a Children's Card Game Forum =/ Ask your parents or your gf' date=' not from from a random 12 year old =/[/b'] The only thing that makes since in this entire thread is bolded in the above quote. Link to comment Share on other sites More sharing options...
Sartorius Posted February 18, 2009 Report Share Posted February 18, 2009 What makes no sense that you are asking Calculus help from a Children's Card Game Forum =/ Ask your parents or your gf' date=' not from from a random 12 year old =/[/b'] The only thing that makes since in this entire thread is bolded in the above quote. Yes. But, the average age of YCM users is 11 actually. Link to comment Share on other sites More sharing options...
Man0waR Posted February 18, 2009 Author Report Share Posted February 18, 2009 well dozens and maybe hundreds are in late teens (SaTuRn PaLaDiN is the oldest I think. Only if YCMaker is like 80 or sumthin') Link to comment Share on other sites More sharing options...
Cyber Altair Posted February 18, 2009 Report Share Posted February 18, 2009 Yes, an 80 year old man would be interested in Yu-Gi-Oh. But that explains the inactivity =D *cough*heartattack*cough* Link to comment Share on other sites More sharing options...
Man0waR Posted February 18, 2009 Author Report Share Posted February 18, 2009 Yes' date=' an 80 year old man would be interested in Yu-Gi-Oh. [b']But that explains the inactivity =D[/b] *cough*heartattack*cough*that's what I meant there *coughmickeymousecough* Link to comment Share on other sites More sharing options...
Careless Whisper Posted February 18, 2009 Report Share Posted February 18, 2009 my claculus professor gave me this- find the derivative if functions K and G are such that: [K]-34.99+[G(X+2x7)]=[G] it makes NO since. but derivative functions are SO easy (like cal.1 easy...) What... Isn't this just solving for each different variable? If so, then this equation would be easy. Either way, I'm gonna see if my friend, Spence can do this problem. He's in AP Calculas, (Advanced Calculas), and he says it's the easy math class he's ever taken. Link to comment Share on other sites More sharing options...
Man0waR Posted February 18, 2009 Author Report Share Posted February 18, 2009 its just the problem makes NO SENSE!! I have till the end of the week to solve. I think its impossible cuz its so messed up. Nothing makes sense... Link to comment Share on other sites More sharing options...
Exyst Posted February 18, 2009 Report Share Posted February 18, 2009 The answer is 42 Why? It always is This. Link to comment Share on other sites More sharing options...
Dark Posted February 18, 2009 Report Share Posted February 18, 2009 What makes no sense that you are asking Calculus help from a Children's Card Game Forum =/ Ask your parents or your gf' date=' not from from a random 12 year old =/[/quote'] You are so lucky you got here first, otherwise I would have posted that. Anyways, on topic. Lol. Uhm... did you try to, skip the problem? :? Link to comment Share on other sites More sharing options...
Lazer Yoshi Posted February 19, 2009 Report Share Posted February 19, 2009 Ask some other Students at school for help. That's what I do. ^_^ Link to comment Share on other sites More sharing options...
Whitey Posted February 19, 2009 Report Share Posted February 19, 2009 my claculus professor gave me this- find the derivative if functions K and G are such that: [K]-34.99+[G(X+2x7)]=[G] it makes NO since. but derivative functions are SO easy (like cal.1 easy...)I'm just a ten year old' date=' so I'm just guessing here...but I think [K']-34.99+[G(X+2x7)]=[G] [K] = 34.99 - 34.99 = 0 + [G (G to me would be 34.99)] = [G] so [K] = [G] since in this sentence, they are both 34.99 Link to comment Share on other sites More sharing options...
Man0waR Posted February 19, 2009 Author Report Share Posted February 19, 2009 no. Think of it as Algebra 1 or whatever. Uhhhh, solve for G or K. Graph the intercepts, graphing EACH common Solution...I guess, I dun know. Its due Friday or my Prof. Gives me extra functions and extra hard Deriveral Equations... Link to comment Share on other sites More sharing options...
Whitey Posted February 19, 2009 Report Share Posted February 19, 2009 Dude, I'm 10, In elementary school WE DONT LEARN ALGEBRA....and I said I was guessing... Link to comment Share on other sites More sharing options...
Careless Whisper Posted February 19, 2009 Report Share Posted February 19, 2009 my claculus professor gave me this- find the derivative if functions K and G are such that: [K]-34.99+[G(X+2x7)]=[G] it makes NO since. but derivative functions are SO easy (like cal.1 easy...)I'm just a ten year old' date=' so I'm just guessing here...but I think [K']-34.99+[G(X+2x7)]=[G] [K] = 34.99 - 34.99 = 0 + [G (G to me would be 34.99)] = [G] so [K] = [G] since in this sentence, they are both 34.99 Where does it say that G = 34.99? If it's solving for K and G, then here, let me try this. [K]-34.99+[GX+14G]=[G]K-34.99+GX+14G=G-14G=-14GK-34.99+GX=-15G+34.99=+34.99 K+GX=-15G+34.99-GX=-GXK=-15G-GX+34.99 (-15G-GX+34.99)-34.99+GX+14G=G34.99-34.99=0-GX+GX=0All this left is -15G+14G=GCombine like terms. -1G=G+1G on both sides.2G=0G=0K=34.99 Link to comment Share on other sites More sharing options...
Raelen Posted February 19, 2009 Report Share Posted February 19, 2009 From what I know, the 2 answers should be... K = 15G - Gx + 34.99 And... G = K - 34.99 all over 15 - x Lol, I've never done calculus... ^_^ Edit: Never mind. Meti beat me to it. =P Link to comment Share on other sites More sharing options...
.arx Posted February 19, 2009 Report Share Posted February 19, 2009 Eh.... Don't you think this problem is a little too hard for sixth graders? Link to comment Share on other sites More sharing options...
Pikachu Posted February 19, 2009 Report Share Posted February 19, 2009 Lol maths. You say a bunch of gibberish and they say 'Wow, you're good at maths!' Link to comment Share on other sites More sharing options...
Felix Culpa Posted February 19, 2009 Report Share Posted February 19, 2009 my claculus professor gave me this- find the derivative if functions K and G are such that: [K]-34.99+[G(X+2x7)]=[G] it makes NO since. but derivative functions are SO easy (like cal.1 easy...) What... Isn't this just solving for each different variable? If so' date=' then this equation would be easy. Either way, I'm gonna see if my friend, Spence can do this problem. He's in AP Calculas, (Advanced Calculas), and he says it's the easy math class he's ever taken.[/quote'] my claculus professor gave me this- find the derivative if functions K and G are such that: [K]-34.99+[G(X+2x7)]=[G] it makes NO since. but derivative functions are SO easy (like cal.1 easy...)I'm just a ten year old' date=' so I'm just guessing here...but I think [K']-34.99+[G(X+2x7)]=[G] [K] = 34.99 - 34.99 = 0 + [G (G to me would be 34.99)] = [G] so [K] = [G] since in this sentence, they are both 34.99Dont ask me if your right. I'm in Geometry. Where does it say that G = 34.99? If it's solving for K and G, then here, let me try this. [K]-34.99+[GX+14G]=[G]K-34.99+GX+14G=G-14G=-14GK-34.99+GX=-15G+34.99=+34.99 K+GX=-15G+34.99-GX=-GXK=-15G-GX+34.99 (-15G-GX+34.99)-34.99+GX+14G=G34.99-34.99=0-GX+GX=0All this left is -15G+14G=GCombine like terms. -1G=G+1G on both sides.2G=0G=0K=34.99 You put it to say -1G=1G so that is improbable and impossible. -1G is the opposite of G Link to comment Share on other sites More sharing options...
Guest Supreme Gamesmaster Posted February 19, 2009 Report Share Posted February 19, 2009 In this case, Youarehere, you forget that zero is its own additive inverse. Should the equation -g = g be obtained, then the equation is as good as solved. so [K] = [G] since in this sentence' date=' they are both 34.99[/quote']If k = g, then the solution set would include all real numbers. [spoiler=I'm getting no such convenient answers.]If k - 34.99 + gx + 14g = 0k - 34.99 = g(x - 14)k = g(x - 14) + 34.99 (gx - 14g + 34.99) - 34.99 + gx + 14g = 0(gx - 14g) + (gx + 14g) = 02gx = 0gx = 0 The way I see it, if x =/= 0, then g = 0; if x = 0, then g =/= 0. [spoiler=Attempt 2]k - 34.99 + g(x - 14) = gk - 34.99 + gx - 14g = gk - 34.99 + gx = 15gk + gx = 15g + 34.99 Sheesh, that x throws a wrench in the works. Link to comment Share on other sites More sharing options...
Careless Whisper Posted February 20, 2009 Report Share Posted February 20, 2009 my claculus professor gave me this- find the derivative if functions K and G are such that: [K]-34.99+[G(X+2x7)]=[G] it makes NO since. but derivative functions are SO easy (like cal.1 easy...) What... Isn't this just solving for each different variable? If so' date=' then this equation would be easy. Either way, I'm gonna see if my friend, Spence can do this problem. He's in AP Calculas, (Advanced Calculas), and he says it's the easy math class he's ever taken.[/quote'] my claculus professor gave me this- find the derivative if functions K and G are such that: [K]-34.99+[G(X+2x7)]=[G] it makes NO since. but derivative functions are SO easy (like cal.1 easy...)I'm just a ten year old' date=' so I'm just guessing here...but I think [K']-34.99+[G(X+2x7)]=[G] [K] = 34.99 - 34.99 = 0 + [G (G to me would be 34.99)] = [G] so [K] = [G] since in this sentence, they are both 34.99Dont ask me if your right. I'm in Geometry. Where does it say that G = 34.99? If it's solving for K and G, then here, let me try this. [K]-34.99+[GX+14G]=[G]K-34.99+GX+14G=G-14G=-14GK-34.99+GX=-15G+34.99=+34.99 K+GX=-15G+34.99-GX=-GXK=-15G-GX+34.99 (-15G-GX+34.99)-34.99+GX+14G=G34.99-34.99=0-GX+GX=0All this left is -15G+14G=GCombine like terms. -1G=G+1G on both sides.2G=0G=0K=34.99 You put it to say -1G=1G so that is improbable and impossible. -1G is the opposite of G Alright, here's a counter example, which happened to be what G actually equaled. What if G = 0. I just completely destroyed your entire theory with one example. This is why I added G to both sides of the equaltion, because I have to get G by itself and on one side of the equation. Which meant that it had to be 0. Also, I realized earlier that I did some math wrong. Like at the beginning, when I combined like terms, I should have gotten a -13G instead of -15G. :| However, after looking over that, I still would have gotten G to equal 0 anyway. Link to comment Share on other sites More sharing options...
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