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Raine's Logic Puzzle #1


Raine

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Wouldn't you just split the group into halves, say numbers 1, 2, 3, and 4.

Then, depending on the answer (if the door to safety is in those 4, or not), you split that group (or the other) into half for the second time. 
Again, go with the group that ends up having the door in it, and split it once more.

So, say it's door six.

My first group doesn't have it. I then toss out numbers 1-4. For guess two, I split 5, 6, 7, and 8, into two groups of two, and suggest one. 

Well, the group with six has the door I want, and the others are useless- leaving me with just two numbers. I suggest one of the two, and instantly know the answer.

^ My take on it, in white ^

Now, if you didn't get told the answers after each question, and only after all three guesses, it would be much harder.

I would attempt something similar, though. 

Feh, I tried for 20 minutes to number crunch for hard mode, it ain't worth it xD

I had some good leads, but I always only got 40-60% chance of being right. 100% is actually interesting, I'mma see what you guys said. 

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Wouldn't you just split the group into halves, say numbers 1, 2, 3, and 4.

Then, depending on the answer (if the door to safety is in those 4, or not), you split that group (or the other) into half for the second time. 

Again, go with the group that ends up having the door in it, and split it once more.

So, say it's door six.

My first group doesn't have it. I then toss out numbers 1-4. For guess two, I split 5, 6, 7, and 8, into two groups of two, and suggest one. 

Well, the group with six has the door I want, and the others are useless- leaving me with just two numbers. I suggest one of the two, and instantly know the answer.

^ My take on it, in white ^

Now, if you didn't get told the answers after each question, and only after all three guesses, it would be much harder.

I would attempt something similar, though. 

Feh, I tried for 20 minutes to number crunch for hard mode, it ain't worth it xD

I had some good leads, but I always only got 40-60% chance of being right. 100% is actually interesting, I'mma see what you guys said. 

Yeah, you split possibilities in half each time. Since you have 3 tries, and 2 to the power of 3 is 8, it works out.

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Yeah, you split possibilities in half each time. Since you have 3 tries, and 2 to the power of 3 is 8, it works out.

I was trying some wacky s*** with 5s and 3s for hard mode. I also tried leaving one number out of calculations for it.

If you leave out, say, 8, in all three of your guesses, and it turns out it's eight, you're instantly right. 

If it's not eight, you left it out of calculations but you know it's not needed.

Trying to work from there for hard mode, no luck yet though.

 

EDIT

1 3 5 7

1 4 5 6

1 2 7 6

Holy s***, it's so close. Sooooo close.

You know if it's 1 because all three light up. You know if it's 8 because none of them do. 

You know if it's two because only one lights up. You know if it's 3 because only one lights up. Again, true with four.

Two light up, it's 5 or 7 (depending on which two light up). Same with 6.

 

So... you know if it's 1, 2, 3, 4, 5, 6, 7, or 8. I think I got it!

Sorry if it sounds choppy, I was just piecing it together myself as I went, haha.

Edit to the edit: Aix's strategy was the same, as I can see now. The goal is to have the three guesses have three unique numbers, a shared number, a number that is left out, and  3 pairs of shared numbers between all three, if that makes sense.

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Ok so you can solve 16 doors with 4 guesses

 

so I think it's a 2^n deal. 

 

N= guesses 2^n= number of doors it can solve


I was trying some wacky s*** with 5s and 3s for hard mode. I also tried leaving one number out of calculations for it.

If you leave out, say, 8, in all three of your guesses, and it turns out it's eight, you're instantly right. 
If it's not eight, you left it out of calculations but you know it's not needed.

Trying to work from there for hard mode, no luck yet though.

 

EDIT

1 3 5 7

1 4 5 6

1 2 7 6

Holy s***, it's so close. Sooooo close.

You know if it's 1 because all three light up. You know if it's 8 because none of them do. 

You know if it's two because only one lights up. You know if it's 3 because only one lights up. Again, true with four.

Two light up, it's 5 or 7 (depending on which two light up). Same with 6.

 

So... you know if it's 1, 2, 3, 4, 5, 6, 7, or 8. I think I got it!

Sorry if it sounds choppy, I was just piecing it together myself as I went, haha.

Edit to the edit: Aix's strategy was the same, as I can see now. The goal is to have the three guesses have three unique numbers, a shared number, a number that is left out, and  3 pairs of shared numbers between all three, if that makes sense.

I got it to be binomial

 

1 in all

 

3 in 2 

3 in 3

 

1 in none

 

Samething forfor 4 guesses and 16 doors

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>Pick different doors

>Whole room is featureless except for numbers 1-8 on doors

>Only a specific door will work

>Others are death

>Only have a vague hint

 

598.gif

OBVIOUSLY THE ANSWER TO THIS CLICHE IS DOOR #4

THE MIDDLE DOOR IS ALWAYS THE CORRECT ONE IN THIS PREDICTABLE PUZZLE

BUT IT'S A TIE BETWEEN 4 AND 5, SINCE DOORS 1 TO 3 AND 6 TO 8 ARE ALL FAKE

DOOR #5 IS ASSUMED TO BE THE CORRECT ONE, BUT ITS NOT; IT'S NOT RIGHT

SO THAT LEAVES DOOR #4, WHICH IS THE ONE THAT'S LEFT

1212636__safe_solo_screencap_animated_di

NOW IF YOU'LL EXCUSE ME, I HAVE A CORRECT DOOR TO WALK THROUGH

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>Pick different doors

>Whole room is featureless except for numbers 1-8 on doors

>Only a specific door will work

>Others are death

>Only have a vague hint

 

598.gif

OBVIOUSLY THE ANSWER TO THIS CLICHE IS DOOR #4

THE MIDDLE DOOR IS ALWAYS THE CORRECT ONE IN THIS PREDICTABLE PUZZLE

BUT IT'S A TIE BETWEEN 4 AND 5, SINCE DOORS 1 TO 3 AND 6 TO 8 ARE ALL FAKE

DOOR #5 IS ASSUMED TO BE THE CORRECT ONE, BUT ITS NOT; IT'S NOT RIGHT

SO THAT LEAVES DOOR #4, WHICH IS THE ONE THAT'S LEFT

1212636__safe_solo_screencap_animated_di

NOW IF YOU'LL EXCUSE ME, I HAVE A CORRECT DOOR TO WALK THROUGH

giphy.gif

RIP Armz

 

The Memeception - August 4th 2016

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